Answer:
[tex] x = 4 \sqrt{3} [/tex]
Step-by-step explanation:
By Pythagoras Theorem:
[tex] {x}^{2} = {( \sqrt{8 \times 4}) }^{2} + {(4)}^{2} \\ \\ {x}^{2} = {( \sqrt{32}) }^{2} + {(4)}^{2} \\ \\ {x}^{2} = 32 + 16 \\ \\ {x}^{2} = 48 \\ \\ x = \sqrt{48} \\ \\ x = \sqrt{ {4}^{2} \times 3} \\ \\ x = 4 \sqrt{3} [/tex]
