quynhannee
quynhannee quynhannee
  • 24-02-2021
  • Mathematics
contestada

1) x-1+5[tex]\sqrt{x-1\\}[/tex]+3=0
4) [tex]x^{4}[/tex] -64=0

Respuesta :

abidemiokin
abidemiokin abidemiokin
  • 01-03-2021

Answer:

See explanation below

Step-by-step explanation:

Find the value of x in each of the following

1) x-1+5√x-1+3=0

5√x-1 = -x -2

Square both sides

25(x-1) = (-x-2)^2

25(x-1) = x^2+4x + 4

25x-25 = x^2+4x + 4

x^2 +4x + 4 - 25x + 25 = 0

x^2 - 21x + 29 = 0

x = 21±√21²-4(29)/2

x = 21±√441-116/2

x = 21±√325/2

x = 21±18.03/2

x = 21+18.03/2 and 21-18.03/2

x = 19.515 and 1.485

4)  x^4-64=0

x^4 = 64

[tex]x = \sqrt[4]{64}[/tex]

x = 2.83

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