Answer:
B
Step-by-step explanation:
Using the rules of radicals
[tex]\sqrt{\frac{a}{b} }[/tex] = [tex]\frac{\sqrt{a} }{\sqrt{b} }[/tex]
Given
[tex]\sqrt{\frac{2}{x} }[/tex] × [tex]\sqrt{\frac{x^2}{8} }[/tex]
= [tex]\sqrt{\frac{2x^2}{8x} }[/tex] ← cancel 2 and 8 and x² and x
= [tex]\sqrt{\frac{x}{4} }[/tex]
= [tex]\frac{\sqrt{x} }{\sqrt{4} }[/tex]
= [tex]\frac{\sqrt{x} }{2}[/tex] → B
