Answer:
103.2 g of AgCl can be made in the reaction
Explanation:
We state the reaction to analyse the problem:
AlCl₃ + 3AgNO₃ → 3AgCl + Al(NO₃)₃
We convert the mass of chloride to moles:
32 g . 1mol/ 133.34g = 0.240 moles
Ratio is 1:3. See the stoichiometry
1 mol of aluminum chloride can produce 3 moles of AgCl
Then, 0.240 will produce (0.240 . 3)/1= 0.720 moles.
We convert the moles to mass: 0.720 mol . 143.32g/1mol = 103.2 g
