Penrdeezyelieshi Penrdeezyelieshi
  • 21-11-2016
  • Mathematics
contestada

Write log3 6 as a logarithm of base 2.

1) (log2)3/(log2)6
2) (log2)6/(log2)3
3) (log3)2/(log6)2
4) (log6)2/ (log3)2 ...?

Respuesta :

JcAlmighty
JcAlmighty JcAlmighty
  • 22-11-2016
The answer is 2) (log2)6/(log2)3.

Use the change-of-base formula: [tex]log_a(x)= \frac{log_b(x)}{log_b(a)} [/tex]

So, if we want to write log3(6) as a logarithm of base 2, in these example a = 3, x = 6, b = 2:
[tex]log_3(6)= \frac{log_2(6)}{log_2(3)}[/tex]
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Raimi Raimi
  • 12-01-2021

Answer:

B. (log2)6

(log2)3

is your answer

Answer Link

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