L5ikenz2iedemefr L5ikenz2iedemefr
  • 21-11-2016
  • Mathematics
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x ^{sqrt{logx}}=10^{8} ...?

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alsteva alsteva
  • 23-11-2016
[tex]x ^{\sqrt{\log{x}}}=10^{8} \\ \\ \log{x ^{\sqrt{\log{x}}}}=\log{10^{8}} \\ \\ \sqrt{\log{x}}\log{x}=8\log{10} \\ \\ \log{x}=t \\ \\ \sqrt{t} \times t=8 \\ \\t^{\frac{3}{2}}=2^3 \\ \\ ( \sqrt{t} )^3=2^3 \\ \\ \sqrt{t} =2 \\ \\ (\sqrt{t})^2 =2^2 \\ \\ t=4[/tex]

[tex]\log{x}=4 \\ \\ 10^{\log{x}}=10^4 \\ \\ x=10^4[/tex]
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