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23-11-2016
Mathematics

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What are the discontinues of the function f(x) = x^2 - 16/6x-24

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nobillionaireNobley nobillionaireNobley

24-11-2016

The function f(x) = (x^2 - 16) / (6x - 24) is discontinuos at
6x - 24 = 0
6x = 24
x = 4.

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