Answer: 2.186 m
Explanation:
formula for molality: (mol solute)/(kg solvent)
Na2CO3 = solute
510g Na2CO3 * ( 1 mol / 106 g) = 4.811 mol solute
ethylene glycol = solvent
2.2 * 10^3 g * ( 1 kg / 1000 g) = 2.2 kg
(4.811/2.2) = 2.186
