Answer: False
=============================================================
Explanation:
The radical is one step away from being fully isolated. We would apply the rule that [tex]\frac{\sqrt{A}}{\sqrt{B}} = \sqrt{\frac{A}{B}}[/tex]
In this case,
[tex]\frac{\sqrt{x+3}}{\sqrt{x-1}} = \sqrt{\frac{x+3}{x-1}}[/tex]
Meaning that the equation
[tex]\frac{\sqrt{x+3}}{\sqrt{x-1}} =3[/tex]
is the same as
[tex]\sqrt{\frac{x+3}{x-1}} = 3[/tex]
From here, we square both sides and use algebra to isolate x.
