vicg4663
vicg4663 vicg4663
  • 22-05-2021
  • Mathematics
contestada

Solve the equation for all values of x.
(8x+9)(49x^2-100)=0

Respuesta :

arvindgaur98 arvindgaur98
  • 22-05-2021

Answer:

[tex]x = \frac{-9}{8} , \frac{-10}{7} , \frac{10}{7}[/tex]

Step-by-step explanation:

8x+9=0

8x=-9

[tex]x = \frac{-9}{8}[/tex]

or

[tex]49x^{2}-100 = 0[/tex]

[tex](7x)^{2} -10^{2} =0[/tex],

[tex](7x+10)(7x-10)=0[/tex]

[tex]7x+10=0, 7x-10=0[/tex]

[tex]7x=-10, 7x=10[/tex]

[tex]x=-\frac{-10}{7}[/tex], [tex]x = \frac{10}{7}[/tex]

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