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  • 24-05-2021
  • Chemistry
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Calculate the Ka of a 0.35M weak acid with a pH of 4.2.

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maacastrobr
maacastrobr maacastrobr
  • 29-05-2021

Answer:

Ka = 1.14x10⁻⁸

Explanation:

First we calculate [H⁺] from the pH:

  • pH = -log[H⁺]
  • [H⁺] = [tex]10^{-pH}[/tex]
  • [H⁺] = 6.31x10⁻⁵ M

For a monoprotic weak acid, the molar concentration of H⁺ of a solution can be expressed as:

  • [H⁺] = √(C*Ka)

Where C is the molar concentration of the weak acid solution.

  • 6.31x10⁻⁵ M = [tex]\sqrt{0.35M*Ka}[/tex]
  • 1.14x10⁻⁸ = Ka
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