Answer:
X= 5i-2, x=5i-2
Step-by-step explanation:
[tex] {x}^{2} - 4x + 29 = 0 \\ x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{4± \sqrt{ - 100} }{2} \\ x = \frac{4±10i}{2} \\ x = 2±5i \\ x = 2 + 5i \: \: or \: \: x = 2 - 5i[/tex]
