Answer:
[tex](6 - 314 - 3x)9x = 10 \\ 56x - 2826x - 27 {x}^{2} = 10 \\ - 2770x - {27x}^{2} = 10 \\ 27 {x}^{2} + 2770x + 10 = 0[/tex]
[tex](6−314−3x)9x=10 \\ 56x−2826x−27 {x}^{2} =10 \\ −2770x−27 {x}^{2} =10 \\ 27 {x}^{2} +2770x+10=0
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