bradleyssummers405
bradleyssummers405 bradleyssummers405
  • 21-06-2021
  • Mathematics
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f(2) 42 g(x) = 2x +3 Find 4) (. Include any restrictions on the domain. O A. 2.2---3 417 2 > 0 B. 47 2 2 r--3, (1) (a) = (4) (a) x A 을 c. (5) (r) = 1,2*0 OD (1) (a= + 2​

f2 42 gx 2x 3 Find 4 Include any restrictions on the domain O A 223 417 2 gt 0 B 47 2 2 r3 1 a 4 a x A 을 c 5 r 120 OD 1 a 2 class=

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eudora eudora
  • 26-06-2021

Answer:

Option D

Step-by-step explanation:

Given f(x) = [tex]\sqrt[3]{4x}[/tex]

g(x) = 2x + 3

Since, [tex](\frac{f}{g})(x)=\frac{f(x)}{g(x)}[/tex]

                     [tex]=\frac{\sqrt[3]{4x}}{2x+3}[/tex]

This function is defined for the denominator is not equal to zero.

(2x + 3) ≠ 0

x ≠ [tex]-\frac{3}{2}[/tex]

Therefore, Option D will be the correct option.

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