Answer:
(-2,0)
Set up quadratic
[tex]y = 5 {x}^{2} + 5x - 10[/tex]
Divide each coefficient by 5
[tex]y = {x}^{2} + x - 2[/tex]
Factor using AC method.
Think of a number that multiply -2 and add to 1. The answer is -1 and 2.
So we write the equation as
[tex](x - 1)(x +2 )[/tex]
Set each parenthesis to zero.
[tex]x = 1[/tex]
[tex]x = - 2[/tex]
The other zero is -2
