Answer:
[tex]\frac{3y+2}{6y^2}\\[/tex]
Step-by-step explanation:
Given the expression
[tex]\frac{3y+2}{3y}/\frac{6y^2+4y}{3y+2} \\= \frac{3y+2}{3y} * \frac{3y+2}{6y^2+4y}\\= \frac{3y+2}{3y} * \frac{3y+2}{2y(3y+2)}\\= \frac{3y+2}{3y} * \frac{1}{2y}\\= \frac{3y+2}{6y^2}\\[/tex]
