22m4uwu7b9 22m4uwu7b9
  • 24-06-2021
  • Mathematics
contestada

anyone know how to do this??

anyone know how to do this class=

Respuesta :

reinhard10158
reinhard10158 reinhard10158
  • 24-06-2021

Answer:

csc²(x)

Step-by-step explanation:

csc(x) = 1/sin(x)

sin²(x) + cos²(x) = 1

=> cos²(x) = 1 - sin²(x)

cos(2x) = cos²(x) - sin²(x) = (1 - sin²(x)) - sin²(x) =

= 1 - 2×sin²(x)

=> 2×sin²(x) = 1 - cos(2x)

sin²(x) = 1/2×(1-cos(2x))

=> 1 - cos(2x) = 2×(1/2×(1-cos(2x)) = 2×sin²(x)

=> 2 / (1-cos(2x)) = 2 / (2×sin²(x)) = 1/sin²(x) =

= 1/sin(x) × 1/sin(x) = csc(x)×csc(x) = csc²(x)

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