yutongliang910 yutongliang910

25-07-2021
Mathematics

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3x + ky = 8
X – 2ky = 5
are simultaneous equations where k is a constant.
Show that x = 3.

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adeebsaad76 adeebsaad76

25-07-2021

Answer:

3X +ky=8 eqn 1

X-2ky=5 eqn 2

but we want to eliminate ky to get our X.

So let's multiply eqn 1 by 2.

We will have 6x +2ky=16 now eqn 3

now we add eqn 1 and 2

We will have 7x=21

divide by 7

x=3

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