Answer:
y = [tex]\frac{4}{3}[/tex] x + 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
8x - 6y + 12 = 0 ( subtract 8x + 12 from both sides )
- 6y = - 8x - 12 ( divide terms by - 6
y = [tex]\frac{-8}{-6}[/tex] x + 2 , that is
y = [tex]\frac{4}{3}[/tex] x + 2 ← in slope- intercept form
