Respuesta :

mhanifa

Answer:

  • 12 and 13

Step-by-step explanation:

Let the integers be a and b, then we have:

  • [tex]a<\sqrt{160} <b[/tex]

If we square all terms we get:

  • [tex]a^2<160<b^2[/tex]

It is now easier to find the squares:

  • [tex]a^2 = 144\\b^2=169[/tex]

Then the integers are:

  • [tex]a= \sqrt{144} =12\\b=\sqrt{169} =13[/tex]

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