giannamoreidc giannamoreidc
  • 25-09-2021
  • Mathematics
contestada

Given that tan θ= -65/72 and that angle θ terminates in quadrant II, then what is the value of cos θ?

Respuesta :

jeremypac8
jeremypac8 jeremypac8
  • 25-09-2021

Answer:

cosθ = [tex]-\frac{72}{97}[/tex]

Step-by-step explanation:

tanθ = -(65/72)

If it is in the 2nd quadrant, this means that y is positive but x is negative

tanθ= opposite/adjacent or (y/x)

tanθ=[tex]\frac{65}{-72}[/tex]

We know that the adjacent value = -72 and the opposite value = 65

The hypotenuse can be get by the following

[tex]\sqrt{(65)^2+(-72)^2} = 97[/tex]

cosθ is just adjacent/hypotenuse

Our adjacent value is -72

Our hypotenuse is 97, therefore

cosθ = [tex]-\frac{72}{97}[/tex]

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