maryamhazmi777 maryamhazmi777

25-09-2021
Mathematics

contestada

taking out common factor
[tex]16(e - w) {}^{2} + 4(e - w) {}^{2} - 8(e - w) {}^{2} [/tex]

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sqdancefan sqdancefan

25-09-2021

9514 1404 393

Answer:

12(e -w)²

Step-by-step explanation:

Quite clearly, the squared value is a factor of each term:

16(e -w)² +4(e -w)² -8(e -w)² = (16 +4 -8)(e -w)² = 12(e -w)²

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