142802lis 142802lis
  • 23-10-2021
  • Mathematics
contestada

What is the value of n in this equation 2^2 x2^n =(2^4)^3

Respuesta :

jimrgrant1 jimrgrant1
  • 23-10-2021

Answer:

n = 10

Step-by-step explanation:

Using the rule of exponents

• [tex]a^{m}[/tex] × [tex]a^{n}[/tex] = [tex]a^{(m+n)}[/tex]

• [tex](a^m)^{n}[/tex] = [tex]a^{mn}[/tex]

Then

2² × [tex]2^{n}[/tex] = [tex](2^4)^{3}[/tex]

[tex]2^{2+n}[/tex] = [tex]2^{12}[/tex]

Since the bases on both sides are equal, both 2 then equate exponents

2 + n = 12 ( subtract 2 from both sides )

n = 10

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