Using Pythagorean theorem
[tex]\\ \sf\longmapsto P^2=H^2-B^2[/tex]
[tex]\\ \sf\longmapsto P^2=8^2-(4\sqrt{3})^2[/tex]
[tex]\\ \sf\longmapsto P^2=64-48[/tex]
[tex]\\ \sf\longmapsto P^2=16[/tex]
[tex]\\ \sf\longmapsto P=4[/tex]
________
[tex] \: [/tex]
a² = c² - b²
a² = 8² - (4√3)²
a² = 64 - 48
a² = 16
a = √16
a = 4
