cpm0506 cpm0506
  • 22-11-2021
  • Mathematics
contestada

5(x-3) -6(x-2) ≤ 8
also please add the steps

Respuesta :

renknee
renknee renknee
  • 22-11-2021

Answer:

x ≥ -11

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

  • [tex](5)(x)+(5)(-3)+(-6)(x)+(-6)(-2) \leq 8[/tex]
  • [tex]5x - 15 -6x + 12 \leq 8[/tex]
  • [tex](5x-6x) + (-15+12) \leq 8[/tex]
  • [tex]-x - 3 \leq 8[/tex]

Step 2: Add 3 to both sides of the inequality.

  • [tex]-x - 3 + 3\leq 8 + 3[/tex]
  • [tex]-x \leq 11[/tex]

Step 3: Divide both sides of the inequality by -1 and flip the sign.

  • [tex]\frac{-x}{-1} \leq \frac{11}{-1}[/tex]
  • [tex]x \geq -11[/tex]

Therefore, the answer is x ≥ -11.

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