camryn1011942 camryn1011942
  • 22-11-2021
  • Mathematics
contestada

5x−19≤1 OR −4x+3<−6

Solve for x

Respuesta :

saltyduck
saltyduck saltyduck
  • 22-11-2021

Answer:

[tex]x \leqslant 4[/tex]

or

[tex]x > \frac{9}{4} [/tex]

hope this helps!

Step-by-step explanation:

[tex]5x - 19 \leqslant 1[/tex]

[tex]5x \leqslant 1 + 19[/tex]

[tex]5x \leqslant 20[/tex]

divide both by 5 and you get

[tex]x \leqslant 4[/tex]

Now for:

[tex] - 4x + 3 < - 6[/tex]

[tex] - 4x < - 6 - 3[/tex]

[tex] - 4x < - 9[/tex]

since 4 isnt divisible by 9 then...

[tex]x > \frac{9}{4} [/tex]

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