adlytle6108 adlytle6108
  • 21-12-2021
  • Physics
contestada

What is the approximate value of k when 30 = e^5k?

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Аноним Аноним
  • 21-12-2021

Answer:

Explanation:

30 = e^5k

ln30 = lne^5k

ln30 = 5k

k = ln30/5

k = 0.68023947...

round to your heart's content.

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