Respuesta :

boatengalbert291
Is wrong please
Answer is (a) 2

Proof
f(x)=(x^2) + 1.


g(x) = x + 2

f[g(-1)]

First considering g(-1)

g(-1)=(-1) + 2 = 1

f[g(-1)] = f(1)

=(1^2) + 1

=1+1=2

Hence f[g(-1)]=2