jonathanjm121004 jonathanjm121004
  • 24-02-2022
  • Chemistry
contestada

How many moles are occupied by 2.2x10^23 particles of copper?

Respuesta :

jcherry99
jcherry99 jcherry99
  • 24-02-2022

Answer:

Explanation:

1mole of copper = 6.02 * 10^23 particles of copper

x mol of copper =2.2 * 10^23 particles

This is a proportion. All you need do is solve using the rules of proportions.

1/x = 6.02 * 10^23/2.2 * 10^23       Cross multiply

6.02 * 10^23x = 1* 2.2*10^23         Divide by 6.02 * 10^23

x = 2.2*10^23 / 6.02* 10^23

x = .365 mols of copper

Answer Link

Otras preguntas

Which organelle can be compared to a security guard who decides whom may enter a building and whom may not?
Birds and reptiles conduct _____ fertilization and lay the eggs outside of the body. a. internal b. external
is a blue whale, rosebush, mushroom, algea, or pine tree a heterotroph or auto troph
What is the solution to the compound inequality?
During which of the following processes do vesicles sometime fuse with lysosomes
When two geologic plates are moving away from each other, a ______ can result.
how does the water get to the leaves in the tops of the tallest trees against the force of gravity?
Which of the following is not a listed provision in any of the treaties with Tribal Nations? Select the best answer choice. A)Friendship and military alliances
Which element is classified as a noble gas at STP? hydrogen oxygen neon nitrogen
Tay-Sachs disease is prominent among African-Americans Italian-Americans Native Americans Jewish-Americans