Kukissanchez04 Kukissanchez04
  • 24-02-2022
  • Physics
contestada

What is the Electric Field strength at a point if a charge of 0.7 Coulombs experiences a
force (Fe) of 123 Newtons?

Respuesta :

leena
leena leena
  • 24-02-2022

Hi there!

Recall the following equation relating electric force to electric field:

[tex]F_E = qE[/tex]

[tex]F_E[/tex] = Force due to electric field (N)
[tex]q[/tex] = Charge of particle (C)
[tex]E[/tex] = Electric Field Strength (N/C)

Rearrange to solve for the Electric Field, and solve.

[tex]E = \frac{F_E}{q} = \frac{123}{0.7} = \boxed{175.714 \frac{N}{C}}[/tex]

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