Angelica11223
Angelica11223 Angelica11223
  • 24-02-2022
  • Mathematics
contestada

PLEASE HELP!!

7. tan B
8. cos B
9. Sin A
10. tan A

PLEASE HELP 7 tan B 8 cos B 9 Sin A 10 tan A class=

Respuesta :

elliottou
elliottou elliottou
  • 24-02-2022

Answer:

Step-by-step explanation:

use SOH CAH TOA to remember tangent sin and cosine equations

Sin = opposite over hypotenuse Cosine Adjacent over Hypotenuse Tangent Opposite over Adjacent

tangent is also equal to sin/cos

tan B = opposite of B/adjacent of B = 3/5

cos B = adjacent/hypotenuse = 5/sqrt(34)

Sin A = opposite/hypotenuse = 5/sqrt(34)

tan A = opposite/adjacent = sin/cos = [ 5/sqrt(34) ]/ [ 3/sqrt(34) ] = 5/3

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