Respuesta :

apologiabiology
ax^2+bx+c=0

expanded, that is the x term

in
(ax+c)(dx+e), the coefient of the b term is cd+ae
so

(2x-1)(1x+5)
the b term is (-1)(1)+(2)(5)=-1+10=9

b is 9
annikavance17

Answer: b=9

Step-by-step explanation:

ax²+bx+c=0

(ax+b)(cx+d)=0

if we expand it, we get

acx²+bcx+adx+bd=0

b=(bc+ad)

(2x-1)(1x+5)

b=bc+ad=(-1*1+2*5)=-1+10=9

b=9