hariharthapa1980 hariharthapa1980

23-03-2022
Mathematics

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In the given figure, O is Center of circle. If AC//DB and angle ABC=50 , find angle ACD

In the given figure O is Center of circle If ACDB and angle ABC50 find angle ACD class=

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xenia168 xenia168

23-03-2022

Answer:

Step-by-step explanation:

m∠ACB = m∠CBD = 90° ⇒ m∠CAB = 90° - 50° = 40° = m∠ABD ( Alternate interior angles )

m∠CBD = 90°

m∠CDB = 50 °

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jdoe0001 jdoe0001

23-03-2022

Check the picture below, notice the tickmarks, both sides are equal and they make twin angles on the "base" side of the isosceles triangle.

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