Answer:
Step-by-step explanation:
let S₁ be the set of factors of 45 that are less or equal to 6:
S₁ : {1 , 3 , 5}
let S₂ be the set of the even numbers that are less or equal to 6:
S₂ : {2 , 4 , 6}
S₁ ∪ S₂ = {1 ,2 , 3 , 4 , 5 , 6}
⇒ card(S₁ ∪ S₂) = 6
Then
p(even or factor of 45) = p(S₁ ∪ S₂) = 6/6 = 1
Therefore
p(even or factor of 45) = 100%
