It is clear that T lies on the perpendicular bisector of NP. See the explanation below.
What is the explanation for the assertion above?
Given that M (X,Y) is the midpoint of NP
X thus = (5+1)/2
= 3
Y = (7+1)/2
= 4
Hence, we have M (3,4)
Consequent on the above:
Slope TM (m') = (4-2) / (3-6) = - 2/3
Slope of NP (m) = (7-1) / (5-1) = 6/4 = 3/2
M' = -1/m
Hence
TM ⊥ NP; and NP ⊥ TM
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