Option D. The most appropriate comparison for the spread is that the interquartile range for town A, 15 degrees is less than that of B.
How to solve for the interquartile range
The inter quartile is solved as Q3 - Q1
This is seen as
For Town A,
30 - 15 = 15 degrees
For town B
40 - 20 = 20 degrees.
Hence we can see that 15 is less than 20, so town A is less than town B. The answer is option D.
Read more on interquartile range here:
https://brainly.com/question/8145995
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