The empirical formula of Lorelai's compound is C₄H₁₀O
Data obtained from the question
- C = 64.8 g
- H = 13.62 g
- O = 21.58 g
- Empirical formula =?
How to determine the empirical formula
Divide by their molar mass
C = 64.8 / 12 = 5.4
H = 13.62 / 1 = 13.62
O = 21.58 / 16 = 1.35
Divide by the smallest
C = 5.4 / 1.35 = 4
H = 13.62 / 1.35 = 10
O = 1.35 / 1.35 = 1
Thus, the empirical formula of the compound is C₄H₁₀O
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