The value of k in the polynomial is 3
How to solve for k?
The quotient is given as:
(x^2+5x+k)/(x+6)
The remainder is 9
Set the denominator to 0
x + 6 = 0
Solve for x
x = -6
This means that:
f(-6) = 9
So, we have:
(-6)^2 + 5(-6) + k = 9
Evaluate
6+ k = 9
Subtract 6 from both sides
k = 3
hence, the value of k is 3
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