Answer:
[tex]-4i\sqrt{2}[/tex]
Step-by-step explanation:
[tex]\sqrt{-162}=\sqrt{-81}\sqrt{2}=9i\sqrt{2} \\ \\ \sqrt{-32}=\sqrt{-16}\sqrt{2}=4i\sqrt{2} \\ \\ \sqrt{-98}=\sqrt{-49}\sqrt{2}=7i\sqrt{2} \\ \\ \therefore \sqrt{-162}+2\sqrt{-32}-3\sqrt{-98}=9i\sqrt{2}+8i\sqrt{2}-21i\sqrt{2}=-4i\sqrt{2}[/tex]
