AlleA44174 AlleA44174
  • 25-10-2022
  • Mathematics
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Find a.Round to the nearest tenth:a10 cm150°12°с=a = [ ? ]cmLaw of Sines: sin A=sin Bbasin cСEnter

Find aRound to the nearest tentha10 cm15012сa cmLaw of Sines sin Asin Bbasin cСEnter class=

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MofeoluwaJ552327 MofeoluwaJ552327
  • 25-10-2022

Answer:

24.0 cm

Explanation:

To find the value of a, we will use the Law of sines, so

[tex]\frac{\sin A}{a}=\frac{\sin B}{b}[/tex]

So, replacing A = 150°, B = 12°, and b = 10 cm, we get:

[tex]\frac{\sin150}{a}=\frac{\sin 12}{10}[/tex]

Now, we need to solve for a. First, cross multiply

[tex]10\cdot\sin 150=a\cdot\sin 12[/tex]

Then, divide by sin12

[tex]\begin{gathered} \frac{10\cdot\sin150}{\sin12}=\frac{a\cdot\sin 12}{\sin 12} \\ \frac{10\cdot(0.5)}{0.208}=a \\ 24.0=a \end{gathered}[/tex]

Therefore, a = 24.0 cm

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