The distance covered by the object is given as,
[tex]d=ut+\frac{1}{2}at^2[/tex]
Plug in the known values,
[tex]\begin{gathered} d=(0\text{ m/s)(9 s)+}\frac{1}{2}(2m/s^2)(9s)^2 \\ =0\text{ m+}81\text{ m} \\ =81\text{ m} \end{gathered}[/tex]
Thus, the distance covered by the object is 81 m.
