Given the following functions and their restrictions
[tex]f(x)=\begin{cases}(x-7)^2-2,\mleft\lbrace x<-4\mright\rbrace \\ -x+3,\mleft\lbrace-4\leq x\leq1\mright\rbrace \\ x+1,\mleft\lbrace x>1\mright\rbrace\end{cases}[/tex]
Check for the function that satisfies f( -4 )
[tex]\text{the function that satifies it is}\Rightarrow f(x)=-x+3[/tex]
Thus,
[tex]f(-4)=-(-4)+3=4+3=7[/tex]
Hence, the value of f ( - 4 )= 7.
