area of triangle with vertices (x1,y1) ; (x2,y2) and (x3,y3) is
(x1 (y2 - y3 ) + x2 ( y3 - y1 )+ x3 ( y1 - y2))/2
hence, substituting the points (x1, y1)= (-2, 1);
( x2, y2)= (0,3) ; and (x3, y3)= (4,-4) in the area formula ,we get
area of triangle =
( -2(3-(-4)) + 0( -4 - 1) + 4(1-3))/2
(-14+0-8)\2
22\2
11 sq unit
