We are given the following information
Amplitude = 15 cm = 0.15 m
Frequency = 30 rpm
We are asked to find the maximum acceleration of the oscillator
The maximum acceleration of the oscillator is given by
[tex]a=A\cdot w^2[/tex]Where A is the amplitude and w is the angular frequency.
[tex]\begin{gathered} w=2\pi f \\ w=2\pi(\frac{30}{60})_{} \\ w=\pi \end{gathered}[/tex][tex]\begin{gathered} a=0.15\cdot(\pi)^2 \\ a=1.48\; \frac{m}{s^2} \end{gathered}[/tex]Therefore, the maximum acceleration is 1.48 m/s^2
