Respuesta :

[tex]\begin{gathered} \text{ u = x}^2\text{ + 1} \\ du\text{ = 2x} \\ \frac{du}{2}\text{ = x}dx \\ \int e^u\frac{du}{2} \\ \frac{1}{2}\int e^udu \end{gathered}[/tex]

The first choice is the correct result

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