Answer:
(x-3)(x+6)
Explanation:
Given the polynomial: x²+3x-18
To factor it, first, we multiply the first and last terms.
[tex]-18\times x^2=-18x^2[/tex]Next, we list add factors of -18.
[tex]\begin{gathered} -18=-1\times18 \\ -18=-2\times9 \\ -18=-3\times6 \end{gathered}[/tex]Next, we determine the factors that add up to the middle term: 3x
These factors are: 6x and -3x.
Replacing the middle term, we have:
[tex]\begin{gathered} x^2+6x-3x-18 \\ =x(x+6)-3(x+6) \\ =(x-3)(x+6) \end{gathered}[/tex]