Respuesta :

Let

x ----> the first consecutive integer number

x+1 ---> the second consecutive integer number

x+2 ---> the third consecutive integer number

so

we have that

x+(x+1)+(x+2)=261

solve for x

3x+3=261

3x=258

x=86

therefore

x=86

x+1=87

x+2=88

The numbers are 86,87 and 88

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