ciara85 ciara85
  • 24-04-2017
  • Mathematics
contestada

L'Hospital's Rule
Lim
X approaches 0 cot2x•sin6x

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jdoe0001 jdoe0001
  • 24-04-2017
[tex]\bf \lim\limits_{x\to 0}\ cot(2x)sin(6x)\implies \lim\limits_{x\to 0}\ \cfrac{cos(2x)}{sin(2x)}sin(6x)\\\\ -----------------------------\\\\ \underline{LH}\qquad \cfrac{-2sin(2x)sin(6x)+cos(2x)6cos(6x)}{2cos(2x)} \\\\\\ \lim\limits_{x\to 0}\ \cfrac{-2sin(2x)sin(6x)+cos(2x)6cos(6x)}{2cos(2x)} \\\\\\ \lim\limits_{x\to 0}\ \cfrac{-0\cdot 0+1\cdot 6\cdot 1}{2\cdot 1}\implies \cfrac{6}{2}\implies 3[/tex]
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