What is the molecular formula of a compound with an empirical formula of C4H9 and a gram-formula mass of 114.0 g/mole?

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26-04-2017
Chemistry

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What is the molecular formula of a compound with an empirical formula of C4H9 and a gram-formula mass of 114.0 g/mole?

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what is the difference between dividing 16 by 2 and finding the square root of 16

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maddigascarthegreat maddigascarthegreat · Answer 1 · 2017-04-26T20:59:08+02:00

maddigascarthegreat maddigascarthegreat

26-04-2017

The formula is easy:

Gram formula mass
----------------------------
Emprical Formula

So if we plug in our own numbers,

114.0
--------
57.116

We get an answer of 1.99, which rounds to 2.
Then, we distribute based off of our empirical formula.

2(C4H9) becomes C8H18.

Our molecular formula is C8H18.
Hope I could help!

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