A triangular prism has a length of 5 inches, a base of 2 inches, a height of 2 inches, and sides of 2 inches and 3 inches. Find the surface area of the prism.
Volume of the Triangular prism = 1/2 (base*height*length) V = 1/2 (2 * 2 * 5) V = 10 cubic inches.
For the surface area, you can divide the prism into parts: It's made of three rectangles and two equal triangles.
For the two triangles: The area of each of the triangles is 1/2(base x height) Area of each triangles = 1/2 (2 * 5) Area of each triangles = 5 inches^2.
For the three rectangles: * one is equal to base x length, Rectangle1 = 2 x 5 Rectangle1 = 10 inches^2.
* another is equal to side 1 x length Rectangle2 = 3 x 5 Rectangle2 = 15 inches^2
* and the last is equal to side 2 x length. Rectangle3 = 3 x 5 Rectangle3 = 15 inches^2
Adding all the components up, 10 + 15 + 15 + 5 + 5 = 50 inches^2
Therefore, the surface area of the prism is greater than volume 50 > 10 hpe this helps:)
